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Geometry Ch11 test #7b
Question from Anya Course: Geometry Chapter/Lesson/Problem11 test7b Issue: I’m supposed to find Angle APM. To find the angle, I used tan APM=20/70, which gives 15.9 degrees. The solutions manual used sin APM=20/70, which gives 16.6 degrees. Sine is...
Algebra Ch5.6 #15
Ch5.6 #15 As before – all are similar so I will pick the harder one. Givens AB = CD AB = 9(x-2) CD = x + 3(x+5) Therefore, 9(x-2) = x + 3(x+5) Now multiply out and solve 9x – 18 = x + 3x + 15 9x – x - 3x = 15 + 18 5x = 33 x = 6.6 Now go back and find the lengths AB =...
Algebra Ch5.6 #14
Now let’s look at Ch 5.6 #14. Parts a-c are similar – so will do part c since the harder. Area = x + 20 = (x-1)4 > I am just stating all things that are equal based on the given. x+20 = (x-1)4 x+20 = 4x -4 > multiplied out 20 + 4 = 4x – x > moved similar...
Algebra Ch5.6 #9
For problem 5.6, parts a-d are all pretty much the same. Here I will do part d) since a hair more complex. The steps the same for the others. Since AB = CD, we can substitute the following AB is x + 6(x+2) CD is 2(x+10) To get x + 6(x+2) = 2(x+10) So to find the...
Geometry 14.2 #22-23
Question from Joy: We are in Geometry 3 rd edition. Chapter 14 lesson 2 number 22-23. Page 582. How do you get 108? The answer in key says 3 x 180/5? Why? I think I missed something important yet simple. I was thinking divide 360/5. What an I doing wrong? Thanks!...
Geometry Ch13.6 #32
For Chap 13, Lesson 6, #32, the basis for the answers is the figure for #6. If we look carefully at the grid, applying the Pythagorean Theorem gives XY^2 = 2^2 + 2^2 = 8, so XY = sqrt8 = 2sqrt2. YZ^2 = 1^2 + 1^2 = 2, so YZ =sqrt2. Therefore XY = 2YZ.Harold Jacobs...
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