Algebra Ch5.6 #14

by | May 3, 2019

Now let’s look at Ch 5.6 #14.

Parts a-c are similar – so will do part c since the harder.

Area = x + 20 = (x-1)4    > I am just stating all things that are equal based on the given.

x+20 = (x-1)4

x+20 = 4x -4  > multiplied out

20 + 4 = 4x – x  > moved similar items to same side

24 =  3x

x = 8

Now we know x, we have to find the sides (ALWAYS GO BACK AND MAKE SURE YOU KNOW WHAT WAS ASKED)

x -1  = 8 – 1 = 7

4 = 4

 

Written By DaleCallahan

Related Posts

Algebra Ch10.2 #3

Algebra Ch10.2 #3

Error in Solutions Manual The Solutions Manual has the answer from the older version of the book (which used a flag of 104 x 235. Flags have grown since then....

Algebra Ch5.6 #15

Ch5.6 #15 As before – all are similar so I will pick the harder one. Givens AB = CD AB = 9(x-2) CD = x + 3(x+5) Therefore, 9(x-2) = x + 3(x+5) Now multiply...

Algebra Ch5.6 #9

For problem 5.6, parts a-d are all pretty much the same. Here I will do part d)  since a hair more complex. The steps the same for the others. Since AB = CD,...

0