Algebra II with Trig Ch1.3 #73

by | Sep 19, 2014

How do we work Algebra II with Trig Chapter 1.3 #73?

A2T - Ch1.3#73

 

 

Solution

a) Area after purple section cut out

A = (20 times 20) – 4(x^2) = -4x^2 + 400 = -4(x^2 – 100)  = -4(x + 10)(x – 10)

b) V = Area of bottom times height = (20-2x)(20-2x) x = (400-80x+4x^2)x = 4x^3 – 80x^2 + 400x = 4x(x^2 – 20x + 100)

 

Written By DaleCallahan

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