by DaleCallahan | Feb 26, 2016 | Geometry, Geometry Chapter 10, Known Geometry Errors
Kerry Asked: In Chp. 10, Lesson 4, Set III Question 4 the textbook asks “Why is QD/AC = DB/CD?” Shouldn’t it be DB/CB instead of DB/CD? Dr. Callahan Answered: Again you are correct. This is an error in the new printing of the 3rd edition by My...
by DaleCallahan | Feb 26, 2016 | Geometry, Geometry Chapter 10, Known Geometry Errors
Kerry wrote: For Ch. 10, Lesson 2, Set III number 4 asks for rectangles with a ratio of 3/4. The key says there are 4 rectangles that have dimensions of 1.5×2. ABHG is correct, but the other three rectangles seem to be wrong. The key lists BDJI (which...
by DaleCallahan | Feb 22, 2016 | Geometry
If you are looking for details on for a transcript for Jacobs Geometry Course, this description should do the trick. Geometry is a branch of mathematics that deals with the understanding of the world around us by using measurement, properties, and relationships of...
by DaleCallahan | Feb 22, 2016 | Algebra, Algebra Tests, Known Algebra Errors
Colleen wrote: I believe I found an error in the answer key in the 5th Ed. Algebra 1 Teachers Guide. On Test 4, #9.d., the answer in the key (p. 88) should be (x – y squared)squared, shouldn’t it, rather than (x + y squared) squared? Dr. Callahan...
by DaleCallahan | Feb 18, 2016 | Algebra
If you are looking for details for a transcript for Elementary Algebra by Jacobs course, here is the description you need. Elementary Algebra (this course is the equivalent of an Algebra I course) provides a formal development of the algebraic skills and concepts...
by DaleCallahan | Feb 12, 2016 | Geometry, Geometry Tests
Question from Kerry: The answer key for the Geometry Midterm Review #74 says the answer is square root of 80, but shouldn’t it be the square root of 52? It says (4-0) squared + (8-2)squared = 16+64, but it should be = 16+36, shouldn’t it? Answer from Dr....
by DaleCallahan | Feb 11, 2016 | Geometry, Geometry Chapter 11
Hannah asked: I am doing Harold Jacobs Geometry, I am on chapter 11 lesson 3. I got to problems 39-41 and got stuck. Dr Callahan Answered: Let us start at #38. We can see that <ABC = 120 so <ADB = 30. Therefore we know AB = BD based on Theorem 10 page 159....
by DaleCallahan | Jan 29, 2016 | Algebra 2wTrig Chapter 1, Algebra II with Trig
Question: We need help on Algebra II with Trig 1.4 #25. How do we get started? Answer: We want to reduce the problem. The first step I take on these kind of problems is to make it easier to see. Looking at what we are given – we can see that the we have two big...
