Contact Us

by | Sep 4, 2013 | Blog

Thanks for visiting AskDrCallahan!  We have people contact us for various reasons – so we decided to place all information here.    Help doing the math! Here is where you would ask about how to work a problem, a possible error in the textbook or teachers guides...

Algebra Teachers Guide Errata

by | Sep 4, 2013 | Algebra, Known Algebra Errors

The teacher guide and tests have some corrections to be found here!   Algebra 1 Test 1 Errors & Notes   Algebra 1 Test 2 Error Log   Algebra Test 6 Number 7   Algebra Test 5   Chapter 9 lesson 6 problem 16 f -The book is fine –but the Solutions Manual has a minus...

Geometry Ch 3.1 #36

by | Sep 3, 2013 | Geometry

Questions: Help with Geometry ch.3.1 #36. We don’t understand how to get the last step in the answer. How does the 4 get under the “pie” and not also under the d square? Thanks     Answer from Dr. Callahan:  Take these steps   A = pi*r^2   and    r=...

Algebra Ch6.1 Set 4 #1

by | Jul 29, 2013 | Algebra

Question: I found a typo in the answer key… chapter 6, lesson 1, Set 4, number 1 should sat that you divide by 5 instead of 7, correct? Thank you!     Answer by Dr Callahan You are correct. This should say divid by 5 instead of...

Algebra Ch9.2 #4

by | May 30, 2013 | Algebra

Question from Renee,  Please confirm the correct answers for Chapter 9 Lesson 2 on page 403–Problem number 4 (a-f). Answers seem wrong in the answer key. Seems to me they should all be “yes” except “d.” Am I wrong? Answer: In this...

Geometry Ch 14.5 #12

by | May 23, 2013 | Geometry

Question from Daniel,  Would you explain problem 12 from lesson 14.5? How exactly do you calculate circular inches?   Answer First, a circular inch is the amount of area taken up by a circle one inch in diameter. So that makes one circular inch = Area = pi*(d/2)^2...

Geometry Ch. 14.2 #16

by | May 20, 2013 | Geometry

Questions from Teresa, I’m in Jacobs Geometry, Chapter 14, Lesson 2. The answer to problem 16 is 9 sin 20 degrees. How do you get that answer?     Answer: First, from #15 you see we count 9 sides. So, n=9. For #16, based on the formula from Theorem 75 on page...
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